Write four solutions for the following equation: $3x + y = 11$.

To find the solutions for the equation $3x + y = 11$,we can express $y$ in terms of $x$:
$y = 11 - 3x$
Now,we substitute different values of $x$ to find the corresponding values of $y$:
$1$. If $x = 0$,then $y = 11 - 3(0) = 11$. So,the solution is $(0, 11)$.
$2$. If $x = 1$,then $y = 11 - 3(1) = 8$. So,the solution is $(1, 8)$.
$3$. If $x = 2$,then $y = 11 - 3(2) = 5$. So,the solution is $(2, 5)$.
$4$. If $x = -1$,then $y = 11 - 3(-1) = 11 + 3 = 14$. So,the solution is $(-1, 14)$.
Thus,four solutions are $(0, 11), (1, 8), (2, 5), (-1, 14)$.